2x^2-54x-220=0

Solution for 2x^2-54x-220=0 equation:

2x^2-54x-220=0

a = 2; b = -54; c = -220;
Δ = b2-4ac
Δ = -542-4·2·(-220)
Δ = 4676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4676}=\sqrt{4*1169}=\sqrt{4}*\sqrt{1169}=2\sqrt{1169}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-2\sqrt{1169}}{2*2}=\frac{54-2\sqrt{1169}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+2\sqrt{1169}}{2*2}=\frac{54+2\sqrt{1169}}{4}
$